Question
Two dice are thrown simultaneously. Find the probability of getting a multiple of 2 on one dice and multiple of 3 on the other dice.
Answer: Option B
Let X be required events and S be the sample space
then X = {(2, 3), (2, 6), (4, 3), (4, 6), (6, 3), (6, 6), (3, 2), (6, 2), (3, 4), (6, 4), (3, 6)}
n(X) = 11, n(S) = 36
Hence, required probability
$$\eqalign{
& = \frac{{n(X)}}{{n(S)}} \cr
& = \frac{{11}}{{36}} \cr} $$
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Let X be required events and S be the sample space
then X = {(2, 3), (2, 6), (4, 3), (4, 6), (6, 3), (6, 6), (3, 2), (6, 2), (3, 4), (6, 4), (3, 6)}
n(X) = 11, n(S) = 36
Hence, required probability
$$\eqalign{
& = \frac{{n(X)}}{{n(S)}} \cr
& = \frac{{11}}{{36}} \cr} $$
Was this answer helpful ?
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