Question
Two cubes have their face painted as either red or blue color. 1st cube has 5 faces red and 1 face blue. The Probability that both the faces show same color on rolling is 12. How many red faces are present on the 2nd cube.
Answer: Option C
:
C
Suppose x faces of cube 2 is red then 6-x will be blue.
P(RR or BB)= 56×x6+16×(6−x)6=12
5x36+(6−x)36=12
4x+6=18
x=3
Hence number of red faces is 3.
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:
C
Suppose x faces of cube 2 is red then 6-x will be blue.
P(RR or BB)= 56×x6+16×(6−x)6=12
5x36+(6−x)36=12
4x+6=18
x=3
Hence number of red faces is 3.
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