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Two cars X and Y start from two places A and B respectively, which are 700km a part at 9:00am.Both the cars run at an average speed of 60km/h. Car X stops at 10:00 am and again starts at 11:00 am while the other car Y continues to run without stopping. When do the two cars cross each other?
Options:
A .  2:40pm
B .  3:20pm
C .  4:10pm
D .  4:20pm
Answer: Option B


Since the speed of X and Y are 60km/h each and the distance between A and B is 700km. 
Distance travelled by x up to 11:00 am is 60km. 
Since x stops at 10:00 am and distance travelled by Y up to 11:00 am is 120km. 
Now distance between them = 700-180 =520km. 
Let they will meet at a distance of x km from X's position. 
Distance travelled by x= x km 
Distance travelled by Y =(520-x)km 
Therefore, x/60 =520-x/60 
=> 2x = 520 
=> X =260 
=> T=260/60 = 4 1/3 
Thus, they will cross each other after 4 1/3h after 11:00 am i.e at 3:20 pm.



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