Question
Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random . What is he probability that the ticket drawn has a number which is a multiple of 3 or 5 ?.
Answer: Option D
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Here , S = (1, 2, 3, 4, ......................................, 19, 20).
Let E = event of getting a multiple of 3 or 5 = ( 3, 6, 9, 12, 15, 18, 5, 10, 20).
`:.` P (E) = `(n(E))/(n(S)) = 9/20`
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