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Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?

Options:
A .   1 2
B .   2 5
C .   8 15
D .   9 20
Answer: Option D

Here, S = {1, 2, 3, 4, ...., 19, 20}.


Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.



Tickets Numbered 1 To 20 Are Mixed Up And Then A Ticket Is D... P(E) =
n(E)
=
9
.
n(S)
20


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