Question
Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at
random. What is the probability taht the ticket drawn has a number which
is a multiple of 3 or 5?
Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at
random. What is the probability taht the ticket drawn has a number which
is a multiple of 3 or 5?
Answer: Option A
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Here S=(1,2,3,4,5,...,19,20).
Let E=event of getting a multiple of 3 or 5
=(3,6,9,12,15,18,5,10,20)
P(E)= n(E)/n(S)
= 9/20.
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