Question
Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random . What is the probability that the ticket drawn bears a number which is multiple of 3 ?
Answer: Option A
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Here, S = (1, 2, 3, 4, ...................................,19, 20)
Let E = event of getting a multiple of 3 = ( 3, 6, 9, 12, 15, 18)
`:.` P (E) = `(n(E))/(n(S)) = 6/20 = 3/10`
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