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Question

Three unbiased coins are tossed.What is the probability of getting at least 2 heads?



Options:
A .  1/2
B .  1/4
C .  1/3
D .  1/8
Answer: Option A

Here S= {TTT, TTH, THT, HTT, THH, HTH, HHt, HHH}.
Let E = event of getting at least two heads
={THH, HTH, HHT, HHH}.
P(E)= n(E) / n(S)
= 4/8.
<=>1/2.




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