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Question

Three unbiased coins are tossed . What is the probability of getting at least  2 heads ?


Options:
A .  `1/4`
B .  `1/2`
C .  `1/3`
D .  `1/8`
Answer: Option B

Here  S = ( TTT, TTH, THT, HTT, THH, HTH, HHT, HHH).

Let E = event of getting at least two  heads  = ( THH, HTH, HHT, HHH)

`:.`   `  P (E) =  (n(E))/(n(S)) = 4/8 = 1/2`



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