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Question

Three unbiased coins are tossed . What is the probability of getting at most  two heads  ?


Options:
A .  `3/4`
B .  `1/4`
C .  `3/8`
D .  `7/8`
Answer: Option D

Here   S = ( TTT, TTH, THT, HTT, THH, HTH, HHT, HHH)

Let   E = Event of getting at most two heads .

Then , E = (TTT, TTH, THT, HTT, THH, HTH, HHT)

`:.`     ` P(E) =  (n(E))/(n(S)) = 7/8`



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