Question
The value of sin−1{cot(sin−1√(2−√34)+cos−1√124+sec−1√2)} is:
Answer: Option A
:
A
cos−1√124=cos−1√32=π6,sec−1√2=π4
sin−1√2−√34=sin−1√4−2√38=sin−1√3−12√2=π12
∴ sin−1√2−√34+cos−1√124+sec−1√2=π2
and sin−1(cotπ2)=sin−10=0
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:
A
cos−1√124=cos−1√32=π6,sec−1√2=π4
sin−1√2−√34=sin−1√4−2√38=sin−1√3−12√2=π12
∴ sin−1√2−√34+cos−1√124+sec−1√2=π2
and sin−1(cotπ2)=sin−10=0
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