Question
The sum of the length , breadth and depth of a cuboid is 19 cm and its diagonal is `5sqrt(5)` cm . It surface area is :
Answer: Option B
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( l + b + h) = 19 and `sqrt(l^2 + b^2 + h^2 ) = 5sqrt(5) and so (l^2 + b^2 + h^2 )` = 125.
Now, ` (l + b + h)^2 = 19^2 rArr (l^2 + b^2+ h^2 ) + 2(lb + bh + lh) ` = 361
`rArr 2(lb + bh + lh ) = (361 - 125) = 236`
`:.` Surface area = 236 `cm^2` .
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