Question
The sum of p consecutive positive integers is 45. What is the value of p?
(1) p is even.
(2) p<9.
Answer: Option D
:
D
Sum of first ten 10 consecutive natural numbers is 45 (p=10)
Also, the sum of 14+15+16 = 45 [453= (15)] (p=3)
Sum of 22+23 = 45 [452=22.5] (p=2)
Sum of 5, 6, 7, 8, 9, 10 = 45 [456=7.5] (p=6)
Thus, using both statements also, the answer cannot be determined.
Alternate Method:
p2(2a+p−1)=45
Now, possible values of p are 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90.
Out of these, two values of p can be considered - 2 and 6.
Thus, the answer cannot be determined.
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:
D
Sum of first ten 10 consecutive natural numbers is 45 (p=10)
Also, the sum of 14+15+16 = 45 [453= (15)] (p=3)
Sum of 22+23 = 45 [452=22.5] (p=2)
Sum of 5, 6, 7, 8, 9, 10 = 45 [456=7.5] (p=6)
Thus, using both statements also, the answer cannot be determined.
Alternate Method:
p2(2a+p−1)=45
Now, possible values of p are 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90.
Out of these, two values of p can be considered - 2 and 6.
Thus, the answer cannot be determined.
Was this answer helpful ?
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