The probabilities of three mutually exclusive events A, B, C are given by 23,14,

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The probabilities of three mutually exclusive events A, B, C are given by

\frac{2}{3}, \frac{1}{4}, a n d \frac{1}{6}

respectively. This statement

Options:

A . Is true

B . is false

C . nothing can be said

D . could be either

Answer: Option B
:
B
Since the events A,B,C are mutually exclusive, we have

P (A ⋃ B ⋃ C) = \frac{2}{3} + \frac{1}{4} + \frac{1}{6} = \frac{13}{12} > 0

Which is not possible , hence the statement is false.

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