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Question


The numbers 44997 and 43080, leave the same remainder when divided by x. Given that 100x999, how many solutions are possible for x?


Options:
A .   1
B .   3
C .   2
D .   >4
E .   3x2 + 17x – 32
Answer: Option C
:
C
This is based on constant remainder theorem.

Take the difference of 44997 and 43080 = 1917.


Number of 3 digit factors =2 (19173=639 and 19179=213)



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