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Question
The numbers 44997 and 43080, leave the same remainder when divided by x. Given that 100x999, how many solutions are possible for x?
Options:
A .  1
B .  3
C .  2
D .  >4
E .  3x2 + 17x – 32
Answer: Option C
:
C
This is based on constant remainder theorem.
Take the difference of 44997 and 43080 = 1917.
Number of 3 digit factors =2(19173=639 and 19179=213)

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