Question
The length of canvas 1.1 m wide required to build a conical tent of height 14 m and the floor area 346.5 sq. m. is :
Answer: Option B
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`pi r^2 = 346.5`
`rArr r^2 = (346.5 xx 7/22) = 441/4`
`rArr r^2 = 441/4`
`rArr r = 21/2`
`:.` ` l = sqrt(r^2 + h^2) = sqrt(441/4 + (14)^2) = sqrt(1225/4) = 35/2`
So , area of canvas needed = `pi r l = (22/7 xx 21/2 xx 35/2) m^2 = ((33 xx 35)/(2)) m^2`
`:.` Length of canvas = `((35 xx 35)/(2 xx 1.1))`m = 525 m.
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