The least number which gives a remainder of 2, 3 and 4 when successively divided

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Question

The least number which gives a remainder of 2, 3 and 4 when successively divided by 3,x and 8 respectively is 71. Find x.

Options:

A . 4

B . 6

C . 5

D . 7

Answer: Option C
:
C

Solving, we get (4x + 3) $\times$ 3+2 = 71 $⟹$ x=5.

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