Question
The digits p, q and r of a three-digit natural number pqr satisfies the condition 49p + 7q + r = 286. Find the sum of the digits of pqr.
Answer: Option A
:
A
Since 49p+7q+r = 286
Or 72p+71q+70r=286
In other words, this question is the conversion of 286 in base 10 to base 7.
pqr in the equivalent of 286 in base 7=(pqr)7=(556)7
Thus, the sum of the digits = 16.
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:
A
Since 49p+7q+r = 286
Or 72p+71q+70r=286
In other words, this question is the conversion of 286 in base 10 to base 7.
pqr in the equivalent of 286 in base 7=(pqr)7=(556)7
Thus, the sum of the digits = 16.
Was this answer helpful ?
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