The diameter of the circle on which the vertices of the quadrilateral lie is?

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The diameter of the circle on which the vertices of the quadrilateral lie is?

Options:

A .

\sqrt{2 p^{2} q}

B .

\frac{p^{2} + q^{2}}{\sqrt{2}}

C .

\sqrt{p^{2} + q^{2}}

D .

\frac{p - q}{\sqrt{2}}

Answer: Option C
:
C

The diameter of the circle = diagonal of the square = 2 $\sqrt{2}$

Substituting in answer options, we get answer as option(c)

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