The type of the controlling expression of a switch statement cannot be of the ty

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The type of the controlling expression of a switch statement cannot be of the type ........

Answer: Option D

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Question 1. What's wrong in the following statement, provided k is a variable of type int? for(k = 2, k....

Question 2. Find the output of the following program. #include void main() { int y=10; if(y++>9 && y++!=10 && y++>11) printf("%d", y....following program. #include void main() { int y=10; if(y++>9 && y++!=10 && y++>11) printf("%d", y); else printf("%d", y); }

Question 3. What is the right choice, if the following loop is implemented? void main() { int num = 0; do{ --num; printf("%d", num);....implemented? void main() { int num = 0; do{ --num; printf("%d", num); }while( ++num >= 0 ); }

Question 4. What will be the value of sum after the following program is executed? void main() { int sum=1, index = 9; do{ index = i....= index – 1; sum *= 2; }while( index > 9 ); }

Question 5. What will be the following code's output if choice = 'R'? switch(choice) { case 'R' : printf("RED"); case 'W' : printf("....: printf("RED"); case 'W' : printf("WHITE"); case 'B' : printf("BLUE"); default : printf("ERROR");break; }

Question 6. What will be the final value of the digit? void main() { int digit = 0; for( ; digit....

Question 7. Consider the following program fragment: for(c=1, sum=0; c....

Question 8. What will be printed if the following code is executed? void main() { int x=0; for( ; ; ) { if( x++ == 4 ) break; contin....x=0; for( ; ; ) { if( x++ == 4 ) break; continue; } printf("x=%d", x); }

Question 9. Consider the following code: void main() { int a[5] = {6,8,3,9,0}, i=0; if(i != 0) { break; printf("%d", a[i]); } else p....0) { break; printf("%d", a[i]); } else printf("%d", a[i++]); } What is the output of the above program?

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