Question
The speed of A and B are in the ratio 3 : 4. A takes 20 minutes more than B to reach a destination. In what time does A reach the destination ?
Answer: Option D
Answer: (d)Ratio of speed = 3 : 4Ratio of time taken = 4 : 3Let the time taken by A and B be 4x hours and 3 x hours respectively.Then, $4x - 3x = 20/60 ⇒ x = 1/3$Time taken by A = 4x hours= $(4 × 1/3)$ hours = 1$1/3$ hoursUsing Rule 9,Here, $S_1 = 3x, S_2 = 4x$$t_2 = y, t_1 = y + 20/60 = y + 1/3$$S_1t_1 = S_2t_2$$3x(y + 1/3) = 4xy$3y + 1 = 4y, y = 1∴ Time taken by A= 1 + $1/3 = 1{1}/3$ hours
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Answer: (d)Ratio of speed = 3 : 4Ratio of time taken = 4 : 3Let the time taken by A and B be 4x hours and 3 x hours respectively.Then, $4x - 3x = 20/60 ⇒ x = 1/3$Time taken by A = 4x hours= $(4 × 1/3)$ hours = 1$1/3$ hoursUsing Rule 9,Here, $S_1 = 3x, S_2 = 4x$$t_2 = y, t_1 = y + 20/60 = y + 1/3$$S_1t_1 = S_2t_2$$3x(y + 1/3) = 4xy$3y + 1 = 4y, y = 1∴ Time taken by A= 1 + $1/3 = 1{1}/3$ hours
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