Answer: Option B
Let AB be tower and BC be its shadow
∴ Let AB = x
$$\eqalign{
& {\text{Then}}\,BC = \sqrt 3 \times x = \sqrt 3 \,x \cr
& \therefore \tan \theta = \frac{{AB}}{{BC}} \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{x}{{\sqrt 3 \,x}} \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{1}{{\sqrt 3 }} \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \tan {30^ \circ } \cr
& \therefore \theta = {30^ \circ } \cr} $$
∴ Angle of elevation of the sun$${\text{ = }}{30^ \circ }$$