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The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet?
Options:
A .  10 a.m
B .  10.30 a.m
C .  11 a.m
D .  11.30 a.m
Answer: Option C


Suppose they meet x hrs after 8 a.m. Then, (Distance moved by first in x hrs) + [Distance moved by second in (x - 1) hrs] = 33060x + 75(x - 1) = 330 => x = 3So, they meet at (8 + 3) i.e., 11 a.m.



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