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Question

The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travel towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 Km/hr. At what time will they meet?
Options:
A .  10.30 a.m.
B .  10 a.m.
C .  12 noon
D .  11 a.m.
Answer: Option D

Answer : Option D

Explanation :

Assume that they meet x hours after 8 a.m.
Then, train1,starting from A , travelling towards B, travels x hours till the trains meet

$MF#%\Rightarrow \text{Distance travelled by train1 in x hours = Speed } \times \text{Time = 60x}$MF#%


Then, train2, starting from B , travelling towards A, travels (x-1) hours till the trains meet

$MF#%\Rightarrow \text{Distance travelled by train2 in (x-1) hours = Speed } \times \text{Time = 75(x-1)}$MF#%


Total distance travelled = Distance travelled by train1 + Distance travelled by train2
=> 330 = 60x + 75(x-1)
=> 12x + 15(x-1) = 66
=> 12x + 15x - 15 = 66
=> 27x = 66 + 15 = 81
=> 3x = 9
=> x = 3
Hence the trains meet 3 hours after 8 a.m., i.e. at 11 a.m.



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