Question
The average speed of a train in the onward journey is 25% more than that in the return journey . The train halts for one hour on reaching the destination . The total time taken for the complete to and for journey is 17 hours. covering a distance of 800 km. The speed of the train in the onward journey is :
Answer: Option D
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Let the speed in return journey by `x` km/hr
Then , speed in onward journey = `125/100 x = (5/4 x)` km/hr
Average speed = `((2 xx 5/4 x xx x)/(5/4 x + x))` km/hr = `(10x)/(9` km/hr
`:.` `(800 xx (9)/(10x)) = 16 hArr x = ((800 xx 9)/(16 xx 10))` = 45.
So, speed in onward journey = `(5/4 xx 45)`km/hr = 56.25 km/hr
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