Question
Starting from his house one day , a student walks at a speed of `2 1/2` kmph and reaches his school 6 minutes late . Next day he increases his speed by 1 kmph and reaches he school 6 minutes early . How far is the school from his house ?
Answer: Option C
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Let the distance be `x` km.
Difference in timings = 12 min. = `12/60 `hr = `1/5` hr.
`:.` ` (2x)/(5) - (2x)/7 = 1/5 `
`hArr 14x - 10x = 7 hArr x = 1 3/4` km.
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