Question
Shown in the figure is a circular loop of radius r and resistance R. A variable magnetic field of induction B = B0e−t is established inside the coil. If the key (K) is closed, the electrical power developed right after closing the switch is equal to
Answer: Option D
:
D
P=e2R;e=−ddt(BA)=−Addt(Boe−t)=ABoe−t
⇒P=1R(ABoe−t)2=A2B2oe−2tR
At the time of starting t = 0 so P=A2B2oR
⇒P=(πr2)2B2oR=B2oπ2r4R
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:
D
P=e2R;e=−ddt(BA)=−Addt(Boe−t)=ABoe−t
⇒P=1R(ABoe−t)2=A2B2oe−2tR
At the time of starting t = 0 so P=A2B2oR
⇒P=(πr2)2B2oR=B2oπ2r4R
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