Set N consists of all natural numbers from 1 to 10. Three numbers are selected

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Set N consists of all natural numbers from 1 to 10. Three numbers are selected at random from this set. Find the probability that the product of two of the number is equal to the third

Options:

A .

\frac{3}{4}

B .

\frac{1}{8}

C .

\frac{2}{8}

D .

\frac{1}{40}

Answer: Option D
:
D

The only set of numbers possible = (2,3,6) (2,4,8) and (2,5,10)
thus required probability = $\frac{3}{^{10} C_{3}}$ = $\frac{1}{40}$

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