One of the two events must occur. If the chance of one is 23 of the other,

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One of the two events must occur. If the chance of one is

\frac{2}{3}

of the other, then odds in favour of the other are

Options:

A . 2:3

B . 1:3

C . 3:1

D . 3:2

Answer: Option D
:
D
Let p be the probability of the other event, then the probability of the first event is

\frac{2}{3}

p. Since two events are totally exclusive, we have

p + (\frac{2}{3}) p = 1 \Rightarrow p = \frac{3}{5}

Hence odds in favour of the other are 3 : 5 – 3, i.e, 3 : 2.

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