Question
On rolling a dice 2 times, the sum of 2 numbers that appear on the uppermost face is 8. What is the probability that the first throw of dice yields 4?
Answer: Option B
A dice has 6 faces
So there are 6 possible outcomes
Dice is rolled once and then again
So total possibilities = 6 × 6 = 36
The sum should be 8 of the 2 throws
So which combination of numbers from 1 to 6 will yield us a sum of 8
They are - (2, 6); (6, 2); (3, 5); (5, 3); (4, 4);
So there are total 5 possibilities where addition is 8.
But only 1 possibility where first throw of dice is 4.
So, Probability for first throw to be 4 and sum to be 8 = $$\frac{{1}}{{36}}$$
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A dice has 6 faces
So there are 6 possible outcomes
Dice is rolled once and then again
So total possibilities = 6 × 6 = 36
The sum should be 8 of the 2 throws
So which combination of numbers from 1 to 6 will yield us a sum of 8
They are - (2, 6); (6, 2); (3, 5); (5, 3); (4, 4);
So there are total 5 possibilities where addition is 8.
But only 1 possibility where first throw of dice is 4.
So, Probability for first throw to be 4 and sum to be 8 = $$\frac{{1}}{{36}}$$
Was this answer helpful ?
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