Let x be a prime number such that x≥23. Given that y= x!+1. The number

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Let x be a prime number such that $x \geq 23$ . Given that y= x!+1. The number of primes in the list y+1, y+2, y+3...y+x-1 is?

Answer: Option D
:
D

For $1 \leq n \leq x - 1, y + n = x! + n + 1$ , which is divisible by n+1 always.
Therefore, there is no prime number in this list.

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