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Question
Let x be a prime number such that x23. Given that y= x!+1. The number of primes in the list y+1, y+2, y+3...y+x-1 is?
Options:
A .  x-1
B .  2
C .  1
D .  None of these
E .  118
Answer: Option D
:
D
For 1nx1,y+n=x!+n+1, which is divisible by n+1 always.
Therefore, there is no prime number in this list.

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