Question
Let x and y be consecutive integers. Suppose m be the number of solutions of x3−y3=3k2 and n be the number of solutions of x3−y3=2t2 , where k, t are integers. Then m + n equals:
Answer: Option D
:
D
Let x=y+1 so, x3−y3=1+3y(y+1) clearly this is not divisible by either 2 or 3 so m = 0 and n = 0 so m+n=0.
Hence option (d)
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:
D
Let x=y+1 so, x3−y3=1+3y(y+1) clearly this is not divisible by either 2 or 3 so m = 0 and n = 0 so m+n=0.
Hence option (d)
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