Question
Let P(n) denote the statement that n2 + n is odd. It
is seem that P(n) ⇒ P(n + 1), Pn is true for all
is seem that P(n) ⇒ P(n + 1), Pn is true for all
Answer: Option D
:
D
P(n) = n2 + n. It is always odd (statement) but
square of any odd number is always odd and
also, sum of odd number is always even. So
for no any 'n' for which this statement is true.
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:
D
P(n) = n2 + n. It is always odd (statement) but
square of any odd number is always odd and
also, sum of odd number is always even. So
for no any 'n' for which this statement is true.
Was this answer helpful ?
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