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Let F(x) = max {(x + 3), (7 – 2x)}. What is the minimum value of F(x) for 2 ≥ x ≥ 1


Options:
A .   4.50
B .   5.00
C .   4.33
D .   4.67
E .   No value Satisfies the given constrins
Answer: Option C
:
C

Please note that we are required to find out the minimum value of F(x), but F(x) always prefer to give the maximum of the two values (i.e., (x + 3), (7 - 2x)).


Thus there is only one possible condition to get the minimum of F(x) that is when both values i.e., (x + 3) and (7 - 2x) are equal.


(x+3) = (7-2x)


3x=4


x=4/3


This satisfies the constraint of 2 ≥ x ≥ 1. Minimum value will occur at x= 4/3 = max (13/3, 13/3) = 13/3 = 4.33



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