Sail E0 Webinar
Question


L and M make an appointment to meet on 20th Nov. 2005 at the CAT examination centre, but without fixing anything other than that the appointment is between 10 a.m. to 11 a.m. They decide to wait no longer than 10 minutes for each other. Assuming that each is independently likely to arrive at any time during the hour, find the probability that they will meet.


Options:
A .   56
B .   2536
C .   1136
D .   None of these
E .   g(n)
Answer: Option C
:
C
There can be 2 approaches to this problem:
Approach 1
We can consider the entire time to be represented by the x-y plot: where on the x-axis we represent the time of one of them coming and on the y-axis the other person coming. L&M will meet provided |x-y|<=10 (x, y) lies on or inside the square with vertices 0(0, 0) A(60, 0) B(60, 60) and C (0, 60).
The region lying inside the square OABC and satisfying the inequality |x - y| > 0 consists two triangles DAE and GFC.
Sum of the areas of two triangles  = 12 (50)212 (50)2 = (50)2
Probability  = 1 - 502602 = 1 - 2536 = 1136
Alternate approach:
The probability that M will not meet L is (5060) (as he cannot meet him any way outside the 10 min he is present at the venue)
Similarly the probability that L will not meet M is also (5060)
Hence the combined probability that they will not meet is 502602
Hence the probability that they will meet will be  = 1 - 502602 = 1 - 2536 = 1136

Was this answer helpful ?
Next Question

Submit Solution

Your email address will not be published. Required fields are marked *

More Questions on This Topic :


Latest Videos

Latest Test Papers