In the unit square, find the distance from E to AD in terms of a and b, the lengths of DF and AG, respectively
Options:
A .  aba+b
B .  ba+b
C .  a−ba+b
D .  aa+b
Answer: Option A : A Let x be the desired distance and y be the distance from E to DF as shown, Since ΔDEF∼ΔGEA,y1−y=ab;y=aa+b Since HE is parallel to side AG of ΔADG, xb=y1;x=aba+b
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