Question
In how many ways can the number 286 be written as a sum of two or more consecutive integers?
Answer: Option A
:
A
Shortcut - Number of ways in which a no. N can be written as a sum of two or more consecutive integers = (No. of odd factors of that number-1)
286=2×11×13. So, it has 4 odd factors - 1, 11, 13, 143.
(No. of odd factors - 1) = 4 - 1 = 3.
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:
A
Shortcut - Number of ways in which a no. N can be written as a sum of two or more consecutive integers = (No. of odd factors of that number-1)
286=2×11×13. So, it has 4 odd factors - 1, 11, 13, 143.
(No. of odd factors - 1) = 4 - 1 = 3.
Was this answer helpful ?
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