Question
In an automated plant assembly line, the rate of rejection of components was 10% on July 1st and 6% on July 2nd . The combined rate of rejection for the two days was 9%. The ratio of production volumes on July 1st and on July 2nd is
Answer: Option C
:
C
Approach 1:Conventional Approach
Ans. (c) Let the production on July 1st and on July 2nd be X and Y units respectively.
Therefore, Rejection on July 1st = 0.1 X
Rejection on July 2nd = 0.06 Y
Therefore, Total rejection = 0.1 X + 0.06 Y = 0.09 (X + Y). Hence, X : Y = 3 : 1
Required ratio is 3:1.
Option (c)
Was this answer helpful ?
:
C
Approach 1:Conventional Approach
Ans. (c) Let the production on July 1st and on July 2nd be X and Y units respectively.
Therefore, Rejection on July 1st = 0.1 X
Rejection on July 2nd = 0.06 Y
Therefore, Total rejection = 0.1 X + 0.06 Y = 0.09 (X + Y). Hence, X : Y = 3 : 1
Required ratio is 3:1.
Option (c)
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution