Question
In a throw of coin what is the probability of getting head.
Answer: Option D
Total cases = [H, T] - 2
Favourable cases = [H] - 1
So probability of getting head = $$\frac{{1}}{{2}}$$
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Total cases = [H, T] - 2
Favourable cases = [H] - 1
So probability of getting head = $$\frac{{1}}{{2}}$$
Was this answer helpful ?
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