Question
In a single throw of die, what is the probability of getting a number greater than 4 ?
Answer: Option B
When a die is thrown, we have S = {1, 2, 3, 4, 5, 6}
Let, E = event of getting a number greater than 4 = {5, 6}
$$\therefore P(E) = \frac{{n(E)}}{{n(S)}} = \frac{2}{6} = \frac{1}{3}$$
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When a die is thrown, we have S = {1, 2, 3, 4, 5, 6}
Let, E = event of getting a number greater than 4 = {5, 6}
$$\therefore P(E) = \frac{{n(E)}}{{n(S)}} = \frac{2}{6} = \frac{1}{3}$$
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