Question
In a simultaneous throw of two dice, what is the probability of getting a total of 10 or 11?
Answer: Option D
In a simultaneous throw of two dice, we have
n (S) = (6 × 6) = 36
Let E = event of getting a total of 10 or 11
= [(4, 6), (5, 5), (6, 4), (5, 6), (6, 5)]
$$\therefore P(E) = \frac{{n(E)}}{{n(S)}} = \frac{5}{{36}}$$
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In a simultaneous throw of two dice, we have
n (S) = (6 × 6) = 36
Let E = event of getting a total of 10 or 11
= [(4, 6), (5, 5), (6, 4), (5, 6), (6, 5)]
$$\therefore P(E) = \frac{{n(E)}}{{n(S)}} = \frac{5}{{36}}$$
Was this answer helpful ?
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