Question
In a simultaneous throw of two dice, what is the probability of getting a doublet ?
Answer: Option A
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In a simultaneous throw of two dice , n (S ) = (6 x 6) = 36.
Let E = event of getting a doublet = {(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6).
`:.` P (E) = `(n(E))/(n(S)) = 6/36 = 1/6`
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