Question
In a simultaneous throw of a pair of dice, find the probability of getting a total more than 7.
Answer: Option A
Was this answer helpful ?
Here, n (S) = ( 6 x 6) = 36.
Let E = Event of getting a total more than 7.
= [(2, 6), (3, 5), ( 3, 6), (4, 4), (4, 5), (4, 6), (5, 3), (5, 4), (5, 5), (5, 6), (6, 2), ( 6, 3), (6, 4), (6, 5), (6, 6)].
`:.` P (E) = `(n(E))/(n(S)) = 15/36 = 5/12`
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution