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In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples?
Options:
A .  5/21
B .  5/14
C .  9/14
D .  16/21
E .  1/3
Answer: Option A


Number of ways of (selecting at least two couples among five people selected) = (⁵Câ‚‚ * ⁶C₁)As remaining person can be any one among three couples left.Required probability = (⁵Câ‚‚ * ⁶C₁)/¹â°Câ‚…= (10 * 6)/252 = 5/21



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