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Question

In a class , there are 15 boys and 10 girls . Three students are selected at random . The probability  that  1 girl and 2 boys are selected , is  :


Options:
A .  `21/46`
B .  `25/117`
C .  `1/50`
D .  `3/25`
Answer: Option A

Let  S be the sample space and  E be he event of selecting  1 girl and 2 boys. Then

n(S) = Number of ways of selecting  3 students out of 25.

        = `25_(C_3) = (( 25 xx 24 xx 23))/((3 xx 2 xx 1))` = 2300

 n(E) = `(10_(C_1) xx 15_(C_2)) = { 10 xx ((15 xx 14))/((2 xx 1))}` = 1050.

`:.`       P(E) = `(n(E))/(n(S)) = 1050/2300 = 21/46`




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