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Question

In a class , 30% of the students offered English , 20%  offered Hindi and 10% offered both . If a student is selected at

random, what is the probability  that he has offered English or Hindi ?


Options:
A .  `2/5`
B .  `3/4`
C .  `3/5`
D .  `3/10`
Answer: Option A

  P(E) = `30/100 = 3/10`,

P (H) = `20/100 = 1/5`

and  `P(E nn H) = 10/100 = 1/10`

 P (E or H) = `P (E uu H)`

                  =` P(E) + P(H) - P(E nn H)`

                = `(3/10 + 1/5 - 1/10) = 4/10 = 2/5`  



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