Question
In a charity show tickets numbered consecutively from 101 through 350 are placed in a box.
What is the probability that a ticket selected at random (blindly) will have a number with a hundredth digit of 2?
What is the probability that a ticket selected at random (blindly) will have a number with a hundredth digit of 2?
Answer: Option B
250 numbers between 101 and 350 i.e. n(S) = 250
n(E) = 100th digits of 2 = 299 - 199 = 100
$$\eqalign{
& P(E) = \frac{{n(E)}}{{n(S)}} \cr
& = \frac{{100}}{{250}} \cr
& = 0.40 \cr} $$
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250 numbers between 101 and 350 i.e. n(S) = 250
n(E) = 100th digits of 2 = 299 - 199 = 100
$$\eqalign{
& P(E) = \frac{{n(E)}}{{n(S)}} \cr
& = \frac{{100}}{{250}} \cr
& = 0.40 \cr} $$
Was this answer helpful ?
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