Question
In how many ways can a committee of 4 people be chosen out of 8 people?
Answer: Option B
Required number of ways
$$\eqalign{
& = {}^8{C_4} \cr
& = \frac{{8 \times 7 \times 6 \times 5}}{{4 \times 3 \times 2 \times 1}} \cr
& = 70 \cr} $$
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Required number of ways
$$\eqalign{
& = {}^8{C_4} \cr
& = \frac{{8 \times 7 \times 6 \times 5}}{{4 \times 3 \times 2 \times 1}} \cr
& = 70 \cr} $$
Was this answer helpful ?
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